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`        a normal cord of the parabolla y^2=4ax subtending a right angle at the vertex makes an acute angle with x axis,the angle is,,,,,,,,,,,,,,,,,,sir plz explain in detail`
7 years ago

147 Points
```										Dear jauneet
let end point of the chord is (at12 ,2at1) and (at22 ,2at2)
since it is normal to parabola  so t2 = -t1  - 2/t1
equation of normal of parabola    y  =-tx + 2at + at3
slope is  -t1   which is given acute  so -t1 >0
or  t1 <0
now chord make right angel at origin   so    {(2at1 -0)/ (at12 -0)}{(2at1 -0)/ (at12 -0)} =-1
t1t2 =-4
t1(-t1  - 2/t1) =-4
t1 =-√2
so    angel is  =tan-1(√2)
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get youthe answer and detailed  solution very  quickly.We are all IITians and here to help you in your IIT JEE preparation.All the best.Regards,Askiitians ExpertsBadiuddin
```
7 years ago
sid
22 Points
```										Can you please explain geometrically this question .I am very confuse about how to draw its figure.
```
10 months ago
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