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drawn from origin are two mutually perpendicular straight lines forming an isosceles triangle together with th straight line 2x+y=a. then the area of the triangle is in terms of 'a'?
(A)a2/2
(B)a2/3
(C)a2/5
(D)none
Dear tejas
length of perpendicular on the line 2x+y=a from the origin is
L = |a|/√5
we know that in right angle triangle mid point of hypotnous is equidistance from all the vertex.
so length of the base = 2L
so area = 1/2 *L *2L
=L2 = a2/5
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