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if the sum of m terms of an ap to the sum of n terms of another ap is m2 to n2 (ratio),show that mth term to nth term is 2m-1 to 2n-1...
The APs have to be the same because their first terms and common difference can't get cancelled out then. Refer NCERT Ex9.2 Q12
Let a and b be the first term and the common difference of the A.P. respectively.
According to the given condition,
Putting m = 2m – 1 and n = 2n – 1 in (1), we obtain
From (2) and (3), we obtain
Thus, the given result is proved.
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