Click to Chat

0120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

Get extra R 550 off
USE CODE: SSPD25

				   Roots Of x4+4x3-4x-13=0?


6 years ago

Share

										Ans:Hello Student,Please find answer to your question

2 years ago

# Other Related Questions on Algebra

If |z|=2 then -1+5z lie on 1).circle 2).parabola . 3).hyperbola

soln

 Nishant Vora one month ago

z’ = 1+5z and so z’+1 = 5z which means |z’+1| = 5|z| = 10 which means z’ lies on a circle centred at (-1,0) and radius 10. Alternatively you can see that 5z takes all points on the circle...

 mycroft holmes one month ago
if (x^5)-(x^3)+ x =a,x>0,then prove that (x^6)>=2a-1

Equivalently we have to prove that or and dividing by x 3 on both sides, we have Setting this is equivalent to the inequality which is same as or From A.M – G.M Inequality, we have 3"...

 mycroft holmes one month ago

Later realized there is a far simpler way: We are given So, as by AM-GM, …........................................................................................

 mycroft holmes one month ago
If |z - 2 + I| ≤2 then find greatest and least possible values of |z|. ( i = √1).

PFA

 Harsh Patodia one month ago
The equation x²/(10-a)+y²(4-a)=1 represents an ellipse if 1)a104 3)4

For ellipse its eccentricity should lie between 0 to 1. 1 – (a-4)^2/(a-10)^2 less than 1 and 1 – (a-4)^2/(a-10)^2 greater than zero. On solving separtely with each interval U would get,...

 Vikas TU 18 days ago
The base BC of triangle ABC is bisected at (p,q) and the equation of sides AB and aAC are px+qy+1 and qx+py=1.Then the equation of median through A is

You no longer have to wait desperately for someone to help resolve your doubt. You can chat with IITians live, 24/7 (even at 3AM!) and get your doubt resolved instantly. Try the HashLearn...

 Ankit 3 months ago

 Ajay 3 months ago
lim(x->a) [(xsina-asinx) /(x-a) ]=sina-acosa........ PROOF

lim [ (xsin(a) - asin(x)) / (x - a) ] x -> a We have to use LHospitals rule to solve this. This means we take the derivative of each of the top and bottom and calculate a new limit. Keep...

 rahul kushwaha 24 days ago
View all Questions »

• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: R 15,000
• View Details
Get extra R 3,750 off
USE CODE: SSPD25

Get extra R 550 off
USE CODE: SSPD25

More Questions On Algebra