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jauneet singh Grade: 12
        

graph of |x|^2+2x+3

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear jauneet


 y =|x|^2+2x+3=x^2+2x+3


(y-2) =(x+1)2


so it is opening upward parabola vertex at (-1,2)










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Badiuddin

7 years ago
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