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Dear ajinkya
to find the area of triangle PRQ ,we should know the co ordinates of point P ,Q ,R
so our task is to find the co-ordinate of P,Q,R
let side of rectangle is a and b
then area of rectangle ABCD =a*b =70(given) .................1
so P will be (a/2,0) (given it is a mid point of AB)
Point S will be (a/3,b) and T will be (2a/3,b)
Point Q is the intersection of line BD and SP
equation of line BD : x/a + y/b =1
equation of line SP : y =-6b/a (x-a/2) { can be easly derived by equation of line from given 2 points)
solve these line and find Q ,Q(2a/5 ,3b/5)
Point R is the intersection of line BD and TP
equation of line TP : y =6b/a (x-a/2) { can be easly derived by equation of line from given 2 points)
solve these line and find R ,Q(4a/7 ,3b/7)
now we know all three points P ,Q and R
use the formula of triangle and find area ,are will come in terms of ab ,put ab =70 from equation 1 , area will come 3 sq unit
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
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