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ajinkya bhole Grade: 10
        in a rectangle ABCD ,P is midpoint of seg.AB.  S & T are points of trisection of seg. DC . if area of the rectangle is 70 sq.units. & a triangle is drawn ie.triangle PST and a diagonal bd of rectangle cuts this triangle in points R  and Q (B-R-Q-D). then find the area of triangle PQR.

i didnt understand ur xplanation plzz xplain again....



7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear ajinkya




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to find the area of triangle PRQ ,we should know the co ordinates of point P ,Q ,R


so our task is to find the co-ordinate of P,Q,R


let side of rectangle is a and b


 then area of rectangle ABCD =a*b  =70(given) .................1


so P will be (a/2,0)    (given it is a mid point of AB)


Point S will be (a/3,b) and T will be (2a/3,b)


Point Q is the intersection of line  BD and SP


 equation of line BD :  x/a + y/b =1


equation of line SP  : y =-6b/a (x-a/2)  { can be easly derived by equation of line from given 2 points)


 solve these line  and find Q   ,Q(2a/5 ,3b/5)




Point R is the intersection of line  BD and TP


 equation of line BD :  x/a + y/b =1


equation of line TP  : y =6b/a (x-a/2) { can be easly derived by equation of line from given 2 points)


 solve these line  and find R   ,Q(4a/7 ,3b/7)




now we know all three points P ,Q and R


use the formula of triangle and find area ,are will come in terms of ab ,put ab =70 from equation 1 , area will come 3 sq unit


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Badiuddin

7 years ago
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