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        factorize
(x+1)(x+2)(x+3)(x+6)-3x2
7 years ago

Jitender Singh
IIT Delhi
158 Points
										Ans:Hello Student,Please find answer to your questionUse simple quadratic formulas now

3 years ago
mycroft holmes
271 Points
										Given expression equals $(x^2+4x+3)(x^2+8x+12)- 3x^2$ Now we have  $3x^2 = 6(x^2+4x+3)-3(x^2+8x+12)+18$ Hence if $A =(x^2+4x+3), B=(x^2+8x+12)$, the given expression can be written out as AB-6A+3B-18 = (A+3)(B-6) which on substituting back for A and B equals $(x^2+4x+6)(x^2+8x+6)$ Both expressions are irreducible over integers and hence you can leave the factorization at this stage

3 years ago
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