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A man firing at a distant target has 10% chance of hitting the taget in one shot.The number of times he must fire at the target to have about 50%chance of hitting the target is
a. 11
b.9
c. 7d. 5
prob of hitting target is 1/10
loosing target is 9/10
so in order to succed in nth shot, he has to fail in (n-1) shots and succed in nth shot
so , here (9/10)(n-1)*(1/10) = (1/2)
on solving n comes nearly to 7 where chace of hitting is arnd 53%
so, n = 7
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regards
Ramesh
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