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```        C is a point outside circle with centre A. and radius "r".
CB and CD  are tangents segments whose length is "t".
find area of triangle BCD in terms of "r" and "t"```
7 years ago

147 Points
```										Dear ajinka

CA = √r2+t2
sinθ =r/√r2+t2
cosθ = t/√r2+t2
AP =rsinθ  = r2/√r2+t2
BP =rcosθ = tr/√r2+t2
ΔBCD = =2ΔBCP = 2[ΔABC -ΔABP]
=2[rt/2   - 1/2 AB * BP]
=rt - {r2/√r2+t2}{ tr/√r2+t2}
=rt - r3t/(r2+t2)
=rt3/(r2+t2)
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed  solution very  quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
```
7 years ago
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