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if p+sin2x+cos4x. then
a)3\4 ≤ p ≤ 1(how ????)
Dear ajinkya
p=sin2x+cos4x
=1-cos2x + cos4x
= 1-cos2xsin2x
=1-1/4 sin22x
for maximum value of P , sin2x =0
P = 1
for minimum value of P ,sin2x=1
P= 1-1/4
=3/4
so 3/4 ≤ p ≤ 1
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