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`        Two non negative integers are chosen at random.The probabability that their sum is divisible by 5 isa.7/25b.8/25c.9/25d.2/5`
7 years ago

SHAIK AASIF AHAMED
74 Points
```										Hello student,Please find the answer to your question belowGivenTwo non negative integers are chosen at random.Let the 2 non -ve integers be a,b then 0<=a,b<=9Number of ways =10*10=100The probabability that their sum is divisible by 5 is=There are 20favorable cases like (0,0)(0,5)(1,4)(2,3)(3,2)(4,1)(5,0)(1,9)(2,8)(3,7)(4,6)(5,5)(6,4)(7,3)(8,2)(9,1)(7,8)(8,7)(9,6)(6,9)So required probability=20/100=1/5
```
3 years ago
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