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```
a fxn is defined on[-1,1]and
area of sq. is 4.
with its vertices at (0,0) and (x,f(x))
then f(x) is...```
7 years ago

147 Points
```										Dear Jauneet
one vertex of square is given (0,0) .then a square of area four can not be formed whose rest three  point  lie in [-1,1]
so such function is not possible,
if (x,f(x) is the vertix of other side of diagonal,and other two vertix can be outside the [-1,1] then square is possible
then length of diagonnal = √{f2(x) +x2}
so area =4 =(digonal)2/2
4= {f2(x) +x2}/2
so f(x) =±√(8-x2)
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```
7 years ago
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