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jauneet singh Grade: 12
        

a fxn is defined on[-1,1]and
area of sq. is 4.
with its vertices at (0,0) and (x,f(x))
then f(x) is...
7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Jauneet


one vertex of square is given (0,0) .then a square of area four can not be formed whose rest three  point  lie in [-1,1]


so such function is not possible,


if (x,f(x) is the vertix of other side of diagonal,and other two vertix can be outside the [-1,1] then square is possible


then length of diagonnal = √{f2(x) +x2}


so area =4 =(digonal)2/2


     4= {f2(x) +x2}/2


 so f(x) =±√(8-x2)


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Badiuddin


 


 

7 years ago
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