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jauneet singh Grade: 12
        


a fxn is defined on[-1,1]and
area of sq. is 4.
with its vertices at (0,0) and (x,f(x))
then f(x) is...


7 years ago

Answers : (1)

Jitender Singh
IIT Delhi
askIITians Faculty
158 Points
										
Ans:
Area of Square: 4
=>The sides of square are of 2 units each.
Diagonal Length:
\sqrt{(f(x))^{2}+x^{2}} = 2\sqrt{2}
(f(x))^{2}+x^{2}} = 8
f(x) = \pm \sqrt{8-x^{2}}
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty
3 years ago
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