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sunny dutta Grade: 12
        f(x)=[x-1/2]+[x+1/2]+2[-x]

range of the function?
7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

f(x)=[x-1/2]+[x+1/2]+2[-x]


let x=I +f  


 where I is integer part of x and 0<= f<1


f(x) =[I+f-1/2]+[I+f+1/2]+2[-I-f]


        =I +[f-1/2] + I +[f+1/2]  -2I +2[-f]


f(x)=[f-1/2]+[f+1/2]+2[-f]


case 1    0=< I <1/2


f(x)= -1 +0 -2   =-3


case 2    1/2=< I <1


f(x)  = 0 +1 -2  =-1


so range is  -1 and -3








 



 


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Badiuddin

7 years ago
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