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`        The no. of roots of the equation x-2/x-2=1-2/x-1 is`
7 years ago

147 Points
```										Dear Pallavi
x- 2/(x-2)=1-2/(x-1)
simplyfie it
f(x)= x3 -4x2 +5x -4=0
now f'(x) = 3x2 -8x +5
discrimnent of this is negative  so
f'(x) >0 for all x
it means f(x) is an incresing function . so it will cut the x axix only at one point so number of real root of this  equation is one
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7 years ago
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