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```        There are 'm' points on a straight line AB and 'n' points on the line AC none of them being the point A. Triangles are formed with these points as vertices, when
(i)A is excluded (ii) A is included. The ratio of no of triangles in the 2 cases is ? ```
7 years ago

147 Points
```										Dear jee king
case 1   A is excluded
total ways =m+nC3
but triangle can't be formebd joining the 3 points which are in straight line so
total number of possible triangle=m+nC3  -mC3  -nC3

Case 2 A is included
otal ways =m+n+1C3
but triangle can't be formebd joining the 3 points which are in straight line so
total number of possible triangle=m+n+1C3  -m+1C3  -n+1C3

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```
7 years ago
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