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There are 'm' points on a straight line AB and 'n' points on the line AC none of them being the point A. Triangles are formed with these points as vertices, when

 (i)A is excluded (ii) A is included. The ratio of no of triangles in the 2 cases is ? 

6 years ago


Answers : (1)


Dear jee king

case 1   A is excluded

total ways =m+nC3

but triangle can't be formebd joining the 3 points which are in straight line so

total number of possible triangle=m+nC3  -mC3  -nC3


Case 2 A is included

otal ways =m+n+1C3

but triangle can't be formebd joining the 3 points which are in straight line so

total number of possible triangle=m+n+1C3  -m+1C3  -n+1C3

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6 years ago

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