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If a<0 and discriminant of ax2+2bx+c=0 is negative then value of
det a b ax+b
b c bx+c = 0
ax+b bx+c 0
Prove this plz........
Dear Sohini,
This is a very simple problem.
It is given that
a < 0 and 4b - 4ac > 0
0r a < 0 and b2 - ac > 0
Now, what you simply have to do is solve the given determinant using the properties which you have learnt and when you expand the equation you have to use a < 0 and b2 - ac > 0, use it and you will get the value of the determinant as 0.
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