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If a<0 and discriminant of ax2+2bx+c=0 is negative then value of

det  a           b          ax+b

        b           c          bx+c          = 0

       ax+b     bx+c       0


Prove this plz........

7 years ago


Answers : (1)


Dear Sohini,

This is a very simple problem.

It is given that

a < 0 and 4b - 4ac > 0

0r a < 0 and b2 - ac > 0

Now, what you simply have to do is solve the given determinant using the properties which you have learnt and when you expand the equation you have to use a < 0 and b2 - ac > 0, use it and you will get the value of the determinant as 0.

7 years ago

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