Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
        limit n tends to infinity.....summation of
r/(n^2+n+r)...from r=1 to r=n is????
a)0.  b)1/3.   c)1/2     d)1
answer is 1/2 ...howww???? plzzz
5 years ago

Jitender Singh
IIT Delhi
158 Points
										Ans:$L = \lim_{n\rightarrow \infty }\sum_{r = 1}^{n}\frac{r}{n^{2}+r+n}$$L = \lim_{n\rightarrow \infty }\frac{1}{n}\sum_{r = 1}^{n}\frac{\frac{r}{n}}{1+\frac{r}{n^{2}}+\frac{1}{n}}$$\frac{r}{n} = x$$\lim_{n\rightarrow \infty }\frac{1}{n} = dx$$L = \int_{0}^{1}x.dx = (\frac{x^{2}}{2})_{0}^{1} = \frac{1}{2}$Thanks & RegardsJitender SinghIIT DelhiaskIITians Faculty

3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details