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`        1/b-c  + 1/b-a  =  1/a  +  1/c`
5 years ago

Latika Leekha
165 Points
```										I am not able to interpret your query. Please write down the problem clearly so that I can provide you the meaningful answer.Thanks & RegardsLatika LeekhaaskIITians faculty
```
3 years ago
SHAIK AASIF AHAMED
74 Points
```										Hello student,a, b, c are in HP, so 1/a, 1/b, 1/c are in AP,->2/b - 1/a = 1/c->(2a - b) / ab = 1/c->c = ab/(2a - b)=1/(b-a) + 1/(b-c) = 1/(b-a) + 1/(b - ab/(2a - b) )= 1/(b-a) + (2a - b)/( b(2a - b) - ab)= 1/(b-a) + (2a - b)/ { b(2a - b - a) }= 1/(b-a) + (2a - b) / {b ( a - b) }= 1/(b-a) - (2a - b) / {b(b-a) }= (b - (2a - b) )/ ( b(b-a) ) =(2b - 2a)/(b(b-a)) = 2(b-a)/(b(b-a)) = 2/b=1/a+1/cHence (1/b-c)+(1/b-a)=1/a+1/cThanks and RegardsShaik AasifaskIITians faculty
```
3 years ago
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