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```         prove that:- 7log16/15+5log25/24+3log81/80=
log2
```
5 years ago

Aman Bansal
592 Points
```										Dear Student,
7log(16/15) + 5log(25/24) + 3log(81/80)= log[(16/15)^7] + log[(25/24)^5] + log[(81/80)^3]= log{[(16^7)*(25^5)*(81^3)] / [(15^7)*(24^5)*(80^3)]}= log{[(2^28)*(5^10)*(3^12)] / [(3^7)*(5^7)*(2^15)*(3^5)*(2^12)*(5^3]}= log{[(2^28)*(3^12)*(5^10)] / [(2^27)*(3^12)*(5^10)}= log(2)

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5 years ago
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