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```				   1) Let a,b be the two positive numbers, where a > b and 4 x GM = 5 X HM for the nos. Then a is

A) 4b
B) 1/4 b
C) 2b
D) b

2) In the value of 100 factorial, the no. of 0s at the end is...
A) 11
B) 22
C) 23
D) 24

3) The sum of all proper divisors of 9900 is
A) 33851
B) 23952
C) 23951
D) none of these

4) In the sequence 1,2,2,3,3,3,4,4,4,4..., where n consecutive terms have value n, the 150th term is
A) 17
B) 16
C) 18
D) none of these

5)log(5c/a), log(3b/5c) and log (a/3b) are in AP, where a, b and c are in GP, then a.a.c are the lengths of the sides of

A) Isoceles Triangle
B) equilateral
C) scalene
D) none

6) The co-efficiant of x^15 in the product (1 - x) ( 1 - 2x) (1 - 4x) ( 1 - 8x) ... (1- 2^15 x) is equal to

A) 2^105 - 2^121
B) 2^121 - 2^105
C) 2^120 - 2^104
D) none of these

7) The co-efficent of x^49 in product (x - 1) (x - 3)...(x - 99) is
A) -99^2
B) 1
C) -2500
d) none of these

8)The sum of n terms of the series 1^2 + 2.2^2 + 3^2 + 2.4^2 +.... is [n(n+1)^2]/2 when n is even. What is sum when n is odd?

9)Th esolution set of mod of [(x +1 )/x] + mod of (X + 1) = (x+1)^2 / mod of (x) is

A) x>= 0
B) x > 0 and x = -1
C) X= -1 or 1
D) none of these

10) mod of [(Z - 1)/(z +1)]= 1 represents
A) circle
B) ellipse
C) a straight line
D) none of these

```

7 years ago

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```										Dear Vishrant Vasvada
a,b be the two positive numbers, where a > b and
4 x GM = 5 X HM
or 4(ab)^.5 =5*2ab/(a+b)
simplify
4(a/b)2 - 17 (a/b) +4 =0
solve
a/b = 4
a=4b
option a is correct
please post seperate question in seperate post

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.  All the best vishrant .  Regards, Askiitians Experts Badiuddin

```
7 years ago
```										4.G.M.=5.A.M.4root(ab)=5(2ab/a+b)5root(ab)(a+b)=10absquaring both side16(a+b)square(ab)=100(ab)square16(a+b)square=100ab16(a+b)square-100ab+016asquare+16bsquare+32ab-100ab=016asquqre+16bsquqre-68ab+04asquare-17ab+4bsquare=04asquqre-16ab-ab+4bsquare=04a(a-4b)-b(a-4b)=0(a-4b)(4a-b)=0hencea=4b
```
one year ago

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