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how many 5 digit numbers of distinct digits can be formedsuch that the middle place isoccupied by largest number?
1 1 2 1 1 = 1 way
x x 3 x x = 2*3*1*3*3
x x 4 x x = 3*4*1*4*4
and so on
x x 9 x x = 8*9*1*9*9
hence total no. of ways = sigma n from 3 to 9 n3 (n-1)
No more cases possible
Hence, answer = 8 × 8 ×7 × 6 + 7 × 7 × 6 × 5 + 6 × 6 × 5 × 4
+ 5 × 5 × 4 × 3 + 4 × 4 × 3 × 2 + 3 × 3 × 2 × 1
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