MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Get instant 20% OFF on Online Material.
coupon code: MOB20 | View Course list

Get extra R 660 off
USE CODE: IND30

				   At a certain stage of a criminal investigation, the inspector in-charge is 60% convince of the guilt of a certain suspect. Suppose now a piece of evidence that shows the criminal has brown hair is uncovered. If the inspector in-charge is convinced that the suspect is not guilty then there is 20% chance that he/she has brown hair. What is the probability that the inspector in-charge is convinced that the suspect is guilty given he/she has brown hair?
				   

4 years ago

Share

Answers : (1)

										Hello student,
Please find the answer to your question below
P(C)=P(C∣G)P(G)+P(C∣Gc)P(Gc)=(1)(0.6)+(0.2)(0.4)=0.68
This is then used to update the inspector's belief in the suspect's guilt posterior to discovering that the suspect does have that characteristic.
P(G∣C)=(P(G)P(C∣G))/P(C)
=1(0.6)/0.68
=0.882
So the probability that the inspector in-charge is convinced that the suspect is guilty given he/she has brown hair is 0.882
2 years ago

Post Your Answer

Other Related Questions on Algebra

If alpha is a real root of the equation ax 2 +bx+c and beta is a real root of equation -ax 2 +bx+c. Show that there exists a root gama of the equation (a/2)x 2 +bx+c which lies between...
 
 
 
Ajay one month ago
 
Small Mistake in last para posting again..............................................................................................................
 
Ajay one month ago
 
We have Similarly, So if P(x) = a/2 x 2 +bx +c, then and are off opposite sign and hence there must exist a root between the two numbers.
 
mycroft holmes one month ago
In the listed image can you tell me how beta*gamma = 2 ….. . . .. ??
 
 
The value of gamma is still not correct, either printing mistake or you gave me wrong value. The correct value of gamma is below
 
Ajay 20 days ago
 
Thankyou so much............................. …......................................................................!
 
Anshuman Mohanty 20 days ago
 
Yes sorry..... . . . .it is not so clear.. ok the values are beta = α + α^2 + α^4 and gamma = α^3 + α^5 + α^7
 
Anshuman Mohanty 21 days ago
Sir que. No. 5.. can u help me... and if u hav some easy tricks to do this que.
 
 
For these type of problems you should convert all logs to a common base e. Also you should know graph of log function so that you can determine if Log a is greater or less than log b. . To...
 
Ajay one month ago
 
Here is rest of solution …................................................................................
 
Ajay one month ago
 
Shorter solution: 1/x = log 5 3 and 1/y = log 25 17 = log 5 >log 5 3 i.e. 1/x 0 we have x>y
 
mycroft holmes one month ago
sin^2 6°-sin^2 12°+sin^2 18°-sin^2 24°......15 solve it Urgent
 
 
Not any people get my answer why. You can no give answer my question I am join this site
 
Vivek kumar one month ago
 
Hello If you want to get the solution quick you should post your question in clear manner. Its not clear what you wnat us to solve, and what does 15 at the end of question means?
 
Ajay one month ago
proove that {cot^a(secA-1)}/1+sinA = sec^2A pls help me solve this problem and thak you
 
 
I hope you want to prove follwing identity. If yes then this not correct question as this can be never be true . For example put A = 45, LHS and RHS are not equal.
 
Ajay one month ago
 
Hi Gaurang the question still does not seem to be correct. Can you post the screenshot of question attachment
 
Ajay one month ago
 
Yes ajay sir I didnt type it correct so it was amistke please help in soving this one and thankyou very much
 
Gaurang Kotasthane one month ago
Solve: (sin theta+cosec theta)^2 + (cos theta +sec theta)^2- (tan^2 theta + cot ^2 theta)^2
 
 
What needs to be solved here ? The question is incomplete....................................................................
 
Ajay one month ago
 
this is the question :: Solve: (sin theta+cosec theta)^2 + (cos theta +sec theta)^2 - (tan^2 theta + cot ^2 theta)
 
Naveen Shankar one month ago
 
i got it open the bracket and simplify and get the answer as 5 …..............................................
 
Naveen Shankar one month ago
View all Questions »

  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 4,500 off
USE CODE: IND30

Get extra R 660 off
USE CODE: IND30

More Questions On Algebra

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details