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find the area of the largest rectangle that can be inscribed in an isosceles triangle of base10ft. and area 30 square ft


 

3 years ago

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Thats 15 sq. feet (according to me)


let the length of the part of base, not included in side of Rectangle be X both side and the vertical side length be Y......


 


Now the rectangle has side lengths, Y and 10-2X.......


now use similar triangle property to find relation b/w Y and X


i.e. Y=6X/5


Hence area = XxY = 6X/5x(10-2X)


Use dA/dX=0 to get X=5/2


Therefore, A=15................Cool

3 years ago

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