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Title: maxima and minima
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Posted On: Feb 17, 2012 10:44 AM
 

find the area of the largest rectangle that can be inscribed in an isosceles triangle of base10ft. and area 30 square ft

 

   
 
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iris berangel
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Feb 17, 2012 02:29 PM

Thats 15 sq. feet (according to me)

let the length of the part of base, not included in side of Rectangle be X both side and the vertical side length be Y......

 

Now the rectangle has side lengths, Y and 10-2X.......

now use similar triangle property to find relation b/w Y and X

i.e. Y=6X/5

Hence area = XxY = 6X/5x(10-2X)

Use dA/dX=0 to get X=5/2

Therefore, A=15................Cool


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