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The number of ways of accomodating 7 guests in 3 rooms so thst no room is empty is


a)1260   b)1440   c)1708   d)1806

4 years ago

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Answers : (1)

										

3^7 - 3*2^7 + 3*1^7 = 2187 - 384 + 3 = 1806


 


Inclusion-Exclusion principle.


 


7 guests go into 3 rooms (1 and 2 rooms can be empty) - 7 guests go into 2 rooms (1 and 2 rooms can be empty) + 7 guests go into 1 room (This was excluded twice)

4 years ago

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10 speakers that includes 3 specific persons (A, B, C) are to speak in a function. Find the number of ways they can be arranged to speak if A has to speak before B and B has to speak before ...
 
 
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Harsh Patodia 3 months ago
 
It will be 7! only 3positions have already been selected. So 7P7 i.e 7! ways.
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Harsh Patodia 3 months ago
 
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PRAPULPODISHETTI 9 months ago
 
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