A  leaf  is  torn  from  a  paperback  novel. The  sum  of  the  numbers  on  the  remaining  pages  is 15000.  What are the page numbers on the torn leaf ?

2 years ago

Share

Answers : (1)

                                        Hello student,
Please find the answer to your question below
The sum of the numbers form an arithmetic progression.
So, assuming the number of pages is n, the first is number 1. And number missing are p and p+1 (a leaf is torn so two page numbers missing).
Then Sum of all pages= n/2 (2+n-1) {using the formula of sum of AP with a=1}
The Sum of remaining pages =15000=n/2(2+n-1)-p-(p+1);
=> 15000= n+n^2/2-n/2-2p-1
=> 15000=n^2/2+n/2-2p-1
=>14999*2=n^2+n-4p
=>4p=n^2+n-14999*2
=>p=(n^2+n-14999*2)*0.25
=>p=(n(n+1)-14999*2)*0.25
Thus knowing the total number of pages you can determine p and p+1 numerically.
one month ago

Post Your Answer

More Questions On Algebra

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
Find the real values of the parameter ‘a’ for which atleast one complex number z =x+iy satisfies both the equality | z- ai | = a+4 and the inequality | z-2 |
 
 
Hello Student, Please find the answer to your question below [|z-ai| = a + 4] [|z-2| < 1] For these two to have atleast one solution, then both circles must intersect [|x+iy-ai| = a+4]...
  img
SHAIK AASIF AHAMED 2 months ago
If set of values of “a” for which f(x) =ax^2 -(3+2a)x+6, a is not equal to zero is positive for exactly three distinct negative integral values of x is (c,d) then the value of (c^2+16 d^2)...
 
 
Hello student, Please find the answer to your question below Givenf(x) =ax^2 -(3+2a)x+6 =(ax-3)(x-2) Here roots of equation f(x)=0 are 2 and 3/a and f(0)=6 f(x) should be positive for...
  img
SHAIK AASIF AHAMED one month ago
No. of solutions of x,where x belongs to [0,2pie] and satisfies the equation, |sin a| +|cos a | = |sin x| where a is any real number. (Plz provide solution with explanation)
 
 
Hello student, Please find the answer to your question below Given|sin a| +|cos a | = |sin x| where a is any real number Squaring LHS we get (|sin a| +|cos a |)2=sin 2 a+cos 2 a+|sin 2a| = 1...
  img
SHAIK AASIF AHAMED one month ago
Please solve this ∫sin 3 x.cos 2 x dx Limit is from -1 to 1
 
 
Ans:Hello student, please find answer to your question
  img
Jitender Singh 2 months ago
prove lhs = rhs (tan a + sec a – 1)/ (tan a – sec a + 1) = sec a + tan a
 
 
Multiplying denominator and numerator by we get,
  img
Satyajit Samal 2 days ago
integrate, ∫ X X dx
 
 
Ans: Hello Student, Please find answer to your question below There is not any standard mathematical expression for this integral. What we can do is expand the integral function around zero...
  img
Jitender Singh 2 months ago
View all Questions »