if A={z belongs to c:z=x+ix-1 for all x belonging to real no.s} and |z|≤|w|,w belongs to A then z is

2 years ago

Share

Answers : (1)

                                        Hello student,
Please find my response to your question below
Iam not able to interpret your query.I think there is some mistake in your question.So please recheck the question and post it again so that i can provide you with a meaningful answer.
2 months ago

Post Your Answer

More Questions On Algebra

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
|z|=1 w=(z-1)/(z+1) re(w) ?
 
 
Hello Student, Thanks & Regards Arun Kumar Btech, IIT Delhi Askiitians Faculty
  img
Arun Kumar 3 months ago
x 1/2 +y=11,x+y 1/2=7
 
 
Hello student, Please find the answer to your question below From(1): x^(1/2) = 7 - y , Letx (1/2) +y=11...........(1) x+y (1/2) =7..........(2) Squaring both sides: x = (7-y)^2 = y^2 - 14y...
  img
SHAIK AASIF AHAMED one month ago
If ax2 - bx +5 = 0 does not have 2 distinct real roots, then find the minimum value of 5a + b?
 
 
Hello student, Please find the answer to your question below Given equation is ax^2-bx+5=0. Since the equation does not have 2 distinct real roots, therefore discriminant 0 i.e. b 2 -20a 0...
  img
SHAIK AASIF AHAMED one month ago
 
ax^2-bx+5=0. Since the equation does not have 2 distinct real roots, therefore discriminant i.e. b^2-20a 20a >/= b^2 5a >/= b^2 /4 5a+b >/= b^2/4 + b. b^2/4 + b is a quadratic equation whose...
 
Sargun Nagpal one month ago
 
ax^2-bx+5=0. Since the equation does not have 2 distinct real roots, therefore discriminant i.e. b^2-20a 20a >/= b^2 5a >/= b^2 /4 5a+b >/= b^2/4 + b. b^2/4 + b is a quadratic equation whose...
 
Sargun Nagpal one month ago
options f(x) is bounded and it takes both of it’s bounds and the range of f(x) contains exactly one integral point. f(x) is bounded and it takes both of it’s bounds and the range of f(x)...
 
 
Hii I have attached a word format of the answer you can consider this for solving Option A is the answer Substitute tanx = t and write the series in terms of t, then use (m+ 1/m) >= 2...
  img
Sourabh Singh one month ago
The complex numbers z1 z2 and z3 satisfying z1- z3/z2 -z3= 1-i(root 3)/2 are vertices of a triangle which is Of arwa 0 eqiulateral right angled isosceles obtuse angle isosceles
 
 
(z1-z2)/(z2-z3)= cos(-60)+sin(-60)=e -i60 taking mode on both sides Absolute value of(z1-z2/z2-z3)=1 Therefore |z1-z2|=|z2-z3| Also angle between z1-z2 & z2-z3 is 60 So given triangle is...
  img
Sunil Raikwar 8 months ago
This is a multiple answer question let a and b be two non null vectors such that |a+b|=|a-2b| . Then the value of |a|/|b| May be : (a) 1/4 (b) 1/8 (c) 1 ( d) 2. Pls solve the question in...
 
 
open the mod like this a+b = +( a=2b) i.e a+b = a-2b which is not possible because b is non null vector. or a+b = -(a-2b) so a/b = 1/2 Thanks Ruchi , Askiitians faculty
  img
ruchi yadav 7 months ago
View all Questions »