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Show that the expression (ax-b)*(cx-d)/(bx-a)*(dx-c) can have all the values for real x if (a*a)-(b*b) and (c*c)-(d*d) have the same sign.

4 years ago

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Answers : (1)

										Hello student,
Please find the answer to your question below
Given(ax-b)*(cx-d)/(bx-a)*(dx-c)
=(acx2-(ad+bc)x+bd)/bdx2-(bc+ad)x+ac
=x2-((d/c)+(b/a))x+(bd/ac)/x2-((c/d)+(a/b))x+(ac/bd)
So by finding the discriminant of the equation from the above we can observe that
the expression (ax-b)*(cx-d)/(bx-a)*(dx-c) can have all the values for real x if (a*a)-(b*b) and (c*c)-(d*d) have the same sign.
one year ago

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1+2+3+....+n=
 
 
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SAIMANIKANTA 5 months ago
 
n(n+1)/2
 
DURGARAM 5 months ago
 
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Kabilan Anbazhagan 6 months ago
 
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Vijay Mukati 6 months ago
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Akshay 7 months ago
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Shantanu Singh 5 months ago
 
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Shantanu Singh 5 months ago
 
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purva gupta 5 months ago
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