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f:R→R  f((x-y)2)= (f(x))2 -2xf(y) +y2 then f(x)=?

7 years ago


Answers : (1)


Setting x = y = 0, we get f(0) = f2(0) which means f(0) = 0 or f(0) = 1


Swapping x and y we get


f[(y-x)2] = f[(x-y)2] = f2(y) - 2y f(x) + x2


Hence we get f2(x) - 2x f(y) + y2 = f2(y) - 2y f(x) + x2


Now putting y = 0, we get f2(x) - 2x f(0)  = f2(0) - x2


If f(0) = 0, then f2(x) = x2 and we get f(x) = x after discarding f(x) = -x as extraneous


Likewise, if f(0) = 1, then f(x) = x+1 satisfies the given equation

7 years ago

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