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pallavi pradeep bhardwaj Grade: 12
        

 A pole stands vertically inside a triangular park Δ ABC. If the angle of elevation of the top of the pole from each corner of the park is same, then in Δ ABC the foot of the pole is at the :
(A) centroid                                 (B) circumcentre
(C) incentre                                 (D) orthocenter.

8 years ago

Answers : (3)

Pavan kumar
18 Points
										

(D) orthocentre


OD is the vertical pole.


Hence <DOA = <DOB = 90


 It is given that <OAD = <OBD


OD is common to both triangle AOD and BOD


Hence triangles AOD and BOD are congruent.


Therefore OA = OB.


Similarly, OA = OC.


Therefore o is equidistant from A,B and C, and hence is at the orthocentre.


4131-2485_6386_untitled.bmp

8 years ago
Ramesh V
70 Points
										

since the angle of elevation of pole is same, which means for a particular height of pole, the distance of pole feet from and any point A,B,C is same


This means that the feet of pole shld be at centroid of triangle ABC


--


regards


Ramesh

8 years ago
AskIITian Expert Priyasheel - IITD
8 Points
										

4138-1770_6754_5.JPG

8 years ago
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