Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        If a and β (α < β) are the roots of the equation x2 + bx + c = 0 , where c < 0 < b, then : (A) 0 < α < β                                             (B) α < 0 < β < ¦α¦ (C) α < β < 0                                              (D) α < 0 < ¦α¦< β `
8 years ago

Ramesh V
70 Points
```										let α, β be roots ,
α + β = -b  and   α*β = c
as c<o and b>0  i.e.,  -b<0
α.β < 0 and    α+β<0
so both α , β must be negative .
as α < β , so the answer is : 0 < α < β
--
regards
Ramesh
```
8 years ago
mycroft holmes
266 Points
```										Option b is right.

Let the roots be p and q. We have p+q<0 and pq<0. This means p<0 and q>0. p+q<0 means q<-p = |p|

Hence we have p<0<q<|p|
```
8 years ago
Sudheesh Singanamalla
114 Points
```										we have Alpha + beta = -b ; alpha*beta = c
As c<0 and b>0 ,we get alpha<0<beta
also Beta = -beta - alpha < - alpha = |Alpha|
thus alpha < 0 < beta < |Alpha|

therefore B is the right option
```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details