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swati sharma Grade:
        

Here is Question .....


x + y + z = 2

x - y + z = 1

x - y - z = 1


solve for x, y and z

8 years ago

Answers : (2)

raj kaushik
26 Points
										

This Question is quite simple ....i solved it ...


check out the solution


equation 1 + equation 2


=>       2(x+z) = 3

             x+z = 3/2

equation 1 +equation3


=>       2x = 3

=>       x = 3/2

equation 2+quation3


=>       2(x-y) =1

             x-y = 1/2

             y = 1

equationj 1 substitute the values of x and y


=>        z=-1/2

8 years ago
anirudh alameluvari
23 Points
										

                                                                                     


                                                                                                 x+y+z = 2  ;   x-y+z=1 ;  x-y-z=1


                                                                                                          x+y+z+x-y+z=3 


                                                                                                             2(x+z) = 3


                                                                                                               x+z=3/2 


                                                                                                            x+y+z+x-y-z = 3


                                                                                                                    2x =3                  


                                                                                                                      x=3/2


                                                                                                                       3/2+z=3/2                                                              


                                                                                                                             z=0


                                                                                                                            x-y-z=1


                                                                                                                            3/2-y-0=1


                                                                                                                              y=1/2


                                                                                                                    (x,y,z) = (3/2,1/2,0)              

8 years ago
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