Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
sneha jha Grade: Upto college level
```          Plz solve this problem....
Express 1296x12 – 4320x9y2 + 5400x6y4 – 3000x3y6 + 625y8 in the form (a + b)n.
```
8 years ago

357 Points
```										I know that the first term is of the form an,          because, for whatever n          is, the first term is nC0          (which always equals 1)          times an          times b0          (which also equals 1).          So 1296x12 =          an. By the same reasoning,          the last term is bn,          so 625y8 = bn.          And since there are alternating "plus" and "minus" signs, I know from experience          that the sign in the middle has to be a "minus". (If all the signs had been "plusses",          then the middle sign would have been a "plus" also. But in this case, I'm really looking          for "(a – b)n".)

I know that, for any power n,          the expansion has n + 1          terms. Since this has 5          terms, this tells me that n          = 4. So to find a          and b,          I only have to take the 4th          root of the first and last terms of the expanded polynomial:

Then a          = 6x3, b = 5y2,          there is a "minus" sign in the middle, and:

1296x12            – 4320x9y2 + 5400x6y4            – 3000x3y6 + 625y8 = (6x3            – 5y2)4

Don't let the Binomial Theorem scare you. It's just        another formula to memorize. A really complicated and annoying formula, I'll grant you, but just        a formula, nonetheless. Don't overthink the Theorem; there is nothing deep or meaningful here.        Just memorize it, and move on.
```
8 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 3,180 off
USE CODE: CHEM20
Get extra Rs. 466 off
USE CODE: CHEM20