solve for x; if


log 7(x3+7)-log7(x+3)=2

3 years ago

Share

Answers : (1)

                                        

log 7(x3+7)-log7(x+3)=2


log(x3+7)/log7 - logx+3/log7 = 2


logx3+7 - logx+3 = 2log7


logx3+7/x+3 = log49


x3+7 = 49x + 49*3


x3 -49x - 20*7 = 0


x3 - 49x - 140 = 0


now solve for x

3 years ago

Post Your Answer

More Questions On Algebra

Ask Experts

Have any Question? Ask Experts
Post Question
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!!
Click Here for details
A polynomial degree'5' we have real roots alfa,beeta.How many roots of have in total
 
 
since the degree of polynomial is 5 no of real roots would be odd (considering the case when two roots are equal). We already know two roots which leave us with two possibility either 3...
  img
sudhir pal 5 months ago
 
Since the polynomial degree is 5, so the polynomial has 5 roots.
 
KATIPERI 5 months ago
 
Thank you sir please justify your answer
 
RAJESH 5 months ago
please solve this question in the image without substitution method?????
 
 
Hello student, Please find the answer to your question below (a)First you need to prove that for positive values of x and y x/y + y/x >= 2 (x - y)² + 2xy = x² + y² Divide...
  img
SHAIK AASIF AHAMED 6 days ago
If p , q, n , l > 0 and the ratio of the roots of equation : lX^2 + nx + n = 0 be p:q then proove that p/q^1/2 + q /p^1/2 – n/l^1/2 = 0
 
 
Hello student, the ratio is p : q so let roots bept and qt. so pt + qt = - n/l => p + q = - n/(lt) and pqt^2 = n/l => pq = n/(lt^2) now (p/q)^1/2 + (q/p)1/^2 = (p + q)/(pq)^(1/2) =...
  img
SHAIK AASIF AHAMED 11 days ago
A bullet loses nth fraction of its velocity while passing through a sandbag. The minimum number of sandbags required to arrest the bullet is?
 
 
the velocity after first bag = v- v/n = v(n-1)/n the velocity after secnod bag = v(n-1)/n- v(n-1)/n^2 = v(n-1)/n(n-1)/n = v(n-1) 2 /n 2 if n=1, means velocity loses complete velocity then 1...
  img
Sher Mohammad 15 days ago
The given figure shows a regular hexagon PQRSTU. Find the value of vector PQ + vector PR + vector PS+ vector PT + vector PU.
 
 
Hello Student, PQ PR=PQ+QR PS=PQ+QR+SR=PR+SR PT=PQ+QR+SR+ST=PS+ST PU=PQ+QR+SR+ST+TU=PT+TU Adding we get =>QR+SR+ST+TU=QU If you give options we'll be able to format the answer in your...
  img
Arun Kumar one month ago
Value of x in the following –
 
 
Image is attached
 
Drake one month ago
View all Questions »