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solve for x; if


log 7(x3+7)-log7(x+3)=2

4 years ago

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Answers : (1)

                                        

log 7(x3+7)-log7(x+3)=2


log(x3+7)/log7 - logx+3/log7 = 2


logx3+7 - logx+3 = 2log7


logx3+7/x+3 = log49


x3+7 = 49x + 49*3


x3 -49x - 20*7 = 0


x3 - 49x - 140 = 0


now solve for x

4 years ago

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