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Sudheesh Singanamalla Grade: 12
        

688_16302_Question.jpg

6 years ago

Answers : (1)

vikas askiitian expert
510 Points
										

a,b,c are terms of ap then


b-a = c-b


 2b = a+c      ..........1


log2 , log2x-1 , log2x+3 are in ap so


2log2x+1 = log2+log2x+3


loga + logb =logab


now expression is


log(2x+1)2 = log[2(2x+3)]


 (2x+1)2 = 2(2x+3)


put 2x = t


(t+1)2 = 2(t+3)


 t = 1,5


2x = 1       or   2x = 5   , x = log5/log2


x = 0 cannot be the solution so x = log5/log2 is the required solution

6 years ago
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