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Aiswarya Ram Gupta Grade: 12
`        n AMs are  inserted between 1 & 51. If ratio between 4th & 7th AMs is 3:5, then n equals??`
6 years ago

## Answers : (2)

510 Points
```										first term of this AP series is 1 , so a =1
now nth term(Tn) = a+(n-1)d                            (d is common ration of this series)
4th term of AMs means 5th term of AP ...so T5 = a+4d = 1+ 4d
7th term of AMs means 8th term of AP ...so T8 = a+7d = 1+7d
ratio is given = 3/5
1+4d/1+7d = 3/5
5+20d = 3+21d
d = 2
now ,let there are n terms  in this Ap then
a + (n-1) = 51
1 + (n-1)2 = 51        or
n = 26
approve my ans if u like it

```
6 years ago
Aiswarya Ram Gupta
35 Points
```										thnx
```
6 years ago
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