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Arvind Petkar Grade:
        

If p and q are two numbers and their LCM is (r square)(t square)(s raised to 4) where r, s, t are prime numbers. Then find the ordered pairs (p,q).


Please Reply.

6 years ago

Answers : (1)

AKASH GOYAL AskiitiansExpert-IITD
419 Points
										

Dear Arvind


p  and  q  are  two  positive  integers  whose  l.c.m.


is r2 s 4 t 2.  This ?rst of all means that neither p  nor q can have any prime


factor besides r, s and t.  So each of them is a product of powers of some


of these three primes.  We can therefore write p, q  in the form


p = ra sb tc    and    q = ru sv tw                             (1)


where a, b, c, u, v, w are non-negative integers.  Then the l.c.m., say e, of p and q is given by


e = ri  sj  tk                                                                                              (2)


where


i = max{a, u},       j = max{b, v}       and    k = max{c, w}                 (3)


This is the key idea of the problem.  The problem is now reduced to ?nding


the  number  of  triplets  of  ordered  pairs  of  the  form  {(a, u), (b, v), (c, w)}


where a, b, c, u, v, w are non-negative integers that satisfy


 


max{a, u} = 2,       max{b, v} = 4       and     max{c, w} = 2                (4)


 


Let us see in how many ways the ?rst entry of this triplet, viz., (a, u)


can be formed.  We want at least one of a and u to equal 2.  If we let a = 2,


then the possible values of u are 0, 1 and 2.  These are three possibilities.


Similarly,  with u  = 2  there will  be  three possibilities,  viz.        a = 0, 1 or 2.


So,  in  all  the  ?rst  ordered pair  (a, u)  can  be  formed  in  6  ways.      But  the


possibility (2, 2) has been counted twice.  So, the number of ordered pairs


of the type (a, u) that satisfy the ?rst requirement in (4) is 5 and not 6.


By  an  entirely  analogous  reasoning,  the  number  of  ordered  pairs  of


the  form  (b, v)  which  satisfy  the  second  requirement  in  (4)  is  2 × 5 − 1,


i.e.  9  while  that  of  ordered  pairs  of  the  type  (c, w)  satisfying  the  third


requirement in (4) is 5.  But the ways these three ordered pairs are formed


are completely independent of each other.  So the total number of triplets


of  ordered pairs  of the  form  {(a, u), (b, v), (c, w)} where  a, b, c, u, v, w  are


non-negative integers that satisfy (4) is 5 ×9 ×5 = 225. 


 


All the best.                                                           


AKASH GOYAL


AskiitiansExpert-IIT Delhi


 


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6 years ago
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