Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
if n is an integer between 0 and 21 ,then the minimum value of n!(21-n)! is _________________
Dear Aatish Agarwal,
Multiply and divide n!(21-n)! by 21!, you get n!(21-n)! = 21!/21 C n
so,minimum value of the given term is same as maximum of 21 C n
we know the max of N c r is for r = n-1/2 if n is odd
therefore for n= 10 or 11 {both same value}, 21 C n is maximum ,hence given term is minimum
THANKS
ALL THE BEST
PLZZZ APPROVE MY ANSWER IF YOU LIKE IT
since minimum value of n!(21-n)! is the maximum value of 21Cn (=21!/n!(21-n)!), therefore it is equal to 10!(21-10)! or 11!(21-11)!, i.e. 11!10!.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !