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aatish agrawal Grade: Upto college level
`        if n is an integer between 0 and 21 ,then the minimum value of    n!(21-n)! is _________________`
7 years ago

Sukhendra Reddy Rompally B.Tech Mining Machinery Engg, ISM Dhanbad
93 Points
```										Dear Aatish Agarwal,
Multiply and divide n!(21-n)! by 21!, you get  n!(21-n)! = 21!/21 C n
so,minimum value of the given term is same as maximum of 21 C n
we know the max of N c r is for r = n-1/2 if n is odd
therefore for n= 10 or 11 {both same value}, 21 C n is maximum ,hence given term is minimum
THANKS
ALL THE BEST
PLZZZ APPROVE MY ANSWER IF YOU LIKE IT
```
7 years ago
RAVI R.
4 Points
```										since minimum value of n!(21-n)! is the maximum value of 21Cn (=21!/n!(21-n)!), therefore it is equal to 10!(21-10)! or 11!(21-11)!, i.e. 11!10!.
```
7 years ago
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