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Dear Student,
Taking Log on both sides,u get xlog1/logi = xlog2
U have log1=0 and log2 is not equal to 0,which means x has o be zero
and that is the only integral solution
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Sorry for the wrong reply,i went wrong somewhere...
Anyways,taking Log on both sides,u get xLog(1-i) = x Log2
multiply and divide 1-i by root 2,u get 1-i/2^0.5 = e^-ipie/4
that is x( 0.5Log2 - i22/28 ) = xLog2
that is xLog2 = -i22/28 and x=0 are the solutions
clearly,x is imaginary if the 1st eqn is true,hence,x=0 is the only integral solution
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