Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Dear Vivek
Question is not clear.i.e. ratio of which circumcircle and which square beacause as mentioned in the question there are many squares ABCD,A1B1C1D1, A2B2C2D2..etc.
All the best.
AKASH GOYAL
AskiitiansExpert-IITD
Please feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation.
Win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar respectively : Click here to download the toolbar..
let the side of outermost square is a....
after drawing the diagram it is clear that radius of circumcircle is 1/21/2 times the side of square ....
side of inner square is 1/21/2 times side of outer square.....
now if the side of outermost square is a then we have
a1,a2,a3,a4....... = a , a/21/2 , a/2 , a/2.21/2 and so on...
r1,r2,r3,r4........ = a/21/2 , a/2 , a/2.21/2 , a/4 and so on
now
area's of circumcircle is ,
Ac = pi(r12 + r22 + r32 ............infinity)
=(pi)a2 (1/2 +1/4 +1/8 +1/16 .....infinity) (sum of infinite GP is a/a-r)
=(pi)a2 ............1
area's of square is ,
As =a2 (1 + 1/2 + 1/4 + 1/8 ...........infinity)
As = 2a2 ...............2
dividing 1 and 2
eq1/eq2=pi/2 independent of radius of circle...
hence option B is correct
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !