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```        If a/(b+c), b/(c+a), c/(a+b) in A.P. and a+b+c is not equal to 0, prove that

1/(b+c), 1/(c+a), 1/(a+b) are in A.P.```
6 years ago

419 Points
```										Dear Chanchal
a/(b+c), b/(c+a), c/(a+b) in A.P.
So
1+a/(b+c),1+ b/(c+a), 1+c/(a+b) in A.P.
(a+b+c)/(b+c), (a+b+c)/(c+a), (a+b+c)/(a+b) in A.P.
1/(b+c), 1/(c+a), 1/(a+b) in A.P.
Hence Proved
All the best.
AKASH GOYAL

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6 years ago
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