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```        Given that x^3a = y^2b = z^4c = xyz,
then 3ab + 4bc + 6ca = ?```
7 years ago

419 Points
```										Dear Vignesh
given
X3a = Y2b = Z4c = XYZ
writing Y and Z in terms of X using above relation
Y=X3a/2b, and Z=X3a/4c
now XYZ = X*X3a/2b*X3a/4c
= X1+(3a/2b)+3a/4c
XYZ    = X(4bc+6ac+3ab)/4bc.........(1)
from given relation XYZ= X3a........(2)
from (1) and (2)
X3a=X(4bc+6ac+3ab)/4bc
3a=(4bc+6ac+3ab)/4bc
hence 3ab + 4bc + 6ca = 12abc  Answer

All the best.
AKASH GOYAL

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7 years ago
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