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`        There are 2 women participants in a chess tournament . the number of men played between themselves exceeded by 52 the number of game they played with the women .if each player played one game with each other, find  the number of men in the tournament `
7 years ago

419 Points
```										Dear Rahul
Let us assume no. of men =n
no. of games played between themselve =nC2
no. games men played with women=2n
According to question
nC2-2n=52
n*(n-1)/2-2n=52
n*n-5n-104=0
After solving
n=13 or -8
-8 is not possible
So no. of men =13
All the bestAKASH GOYALAskiitiansExpert-IITDPlease  feel free to post as many doubts on our discussion forum as you can. We  are all IITians and here to help you in your IIT JEE preparation. Now  you can win exciting gifts by answering the questions on Discussion  Forum. So help discuss any query on askiitians forum and become an Elite  Expert League askiitian.
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7 years ago
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