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There are 2 women participants in a chess tournament . the number of men played between themselves exceeded by 52 the number of game they played with the women .if each player played one game with each other, find the number of men in the tournament
Dear Rahul
Let us assume no. of men =n
no. of games played between themselve =nC2
no. games men played with women=2n
According to question
nC2-2n=52
n*(n-1)/2-2n=52
n*n-5n-104=0
After solving
n=13 or -8
-8 is not possible
So no. of men =13
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