Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        four tickets 00.01,10,11 respectively are placed ina bag . aticket is drawn at random five times being replaced each time the probability that the sum on the tickets is 22 is`
7 years ago

419 Points
```										Dear Phani
There are 3 cases to get sum 22
1) 11+11+00+00+00
It can be done with prob of (5!/(3!*2!))*(1/4)^5
2)10+01+10+01+00
It can be done with prob of (5!/(2!*2!*1!))*(1/4)^5
3)11+10 +01+00+00
It can be done with prob of (5!/(2!*1!*1!*1!))*(1/4)^5
So total probability is sum of three which is 25/256

All the bestAKASH GOYALAskiitiansExpert-IITDPlease feel free to post as many doubts on our discussion forum as you can. We are all IITians and here to help you in your IIT JEE preparation. Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.
```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details
Get extra Rs. 3,180 off
USE CODE: CHEM20
Get extra Rs. 466 off
USE CODE: CHEM20