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chua kok tong Grade: Upto college level
`        You are given a sequence 1,1,2,3,5,8,13,21,... , what is the remainder of 2500 term when divided by8`
7 years ago

85 Points
```										Dear  Chua kok tong,

1,   1,   2,        3,        5,        8,          13,         21,...  34  55
1+1,   1+2,    2+3,   3+5,       8+5,        ......
Let n be the 2500 term, so,   (n-1)th term + ( n-2)th term = nth term
and     (n+2)th term - (n+1 )th term = nth term
0, 1,   1,   2,        3,        5,        8,          13,         21.......
this is called as Fibonacci series, the direct formula is..
F(n)=[ {(1+√5)/2}n-{(1-√5)/2}n ]/√5
given sequence starts from 1 so we will find 2501 th term, so n = 2501
find value and divide by 8.

All the best.
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IIT Bombay
```
7 years ago
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