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```        if the root of the equation x2-ax+b=0 differ by unity

a2 is equal to
1+a2 is equal to
if one of the root of the equation x2-ax+b=0 be twice the other then 2a2 is equal to
if the sum of the root of the equation x2-ax+b=0 is equal to the sum of the square of their reciprocal then a2 is equal to
```
7 years ago

SAGAR SINGH - IIT DELHI
879 Points
```										Dear jiya,
Let p ad p+1 be the roots
p+p+1=a
P(P+1)=b
p=a-1/2
(a-1)/2(a-1/2+1)=b
a^2-1=4b
a^2=4b+1
a^2+1=4b+2

We are all  IITians and here to help you in your IIT  JEE preparation.  All the best.

Sagar Singh
B.Tech IIT Delhi
sagarsingh24.iitd@gmail.com

```
7 years ago
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