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if a=cosθ+isinθ ,b=cosΦ+isinΦ ,c=cosψ+isinΨ and a⁄b+b/c+c/a=1 then cos(θ-Φ)+cos(Φ-ψ)+cos(ψ-θ) equals _________
if eiθ =cosθ+isinθ then e2micot-1p(pi+1/pi-1)equals
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7 years ago

42 Points
```										Dear Khushboo,You can write a=eθ, b=eΦ, c=eΨ
Now a/b+b/c+c/a = eθ-Φ+eΦ-Ψ+eΨ-θ = 1 (given). Taking the real part of both the sides you get cos(θ-Φ)+cos(Φ-ψ)+cos(ψ-θ)=1Please feel free to post as many doubts on our discussion forum as you can.we will get you the answer and detailed  solution very  quickly. All the best.Regards,Askiitians Experts,Gokul  Joshi
```
7 years ago
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