Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        What is the number of solutions (x, y) of the equation 3x+y=100, where x and y are positive integers?`
7 years ago

Chanchal Kumar
31 Points
```										The given equation can be rewritten as y=100-3x ----- (i)
since, the minimum value of x can be 0,hence putting this value in eq (i), we get y=100 which is the maximum value of y
and minimum value of y can be 0 since it is positive integer.
hence, y is an element of [0,100] under given condition --------(ii)
now, the given equation can be rewritten as x=100-y/3-----(iii)
putting minimum and maximum value of y from eq (ii) in eq (iii) we get,
x is an element of [0,33] when x is positive integer----(iv)
from eq (ii) and eq (iv)
0 to 33 is the common value for x and y,
Hence, Number of solution for (x,y) of the equation 3x+y=100 is  34
```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »
• Complete JEE Main/Advanced Course and Test Series
• OFFERED PRICE: Rs. 15,900
• View Details