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`        let  a, b be the roots of the equation  x^2-10cx-11d=0 and c,d be the roots of x^2 -10ax-11b=0, Find the value of a+b+c+d.`
7 years ago

110 Points
```										As a + b = 10c and c + d = 10aab = -11d , cd = -11bac = 121 and (b + d) = 9(a + c)a2 - 10ac - 11d = 0c2 - 10ac - 11b = 0a2 + c2 - 20ac - 11(b + d) = 0(a + c)2 - 22(121) - 11 × 9(a + c) = 0(a + c) = 121 or -22 (rejected)a + b + c + d = 1210.Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.DO APPROVE IF THE ANSWER HELPS YOU.Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.Regards,Askiitians ExpertsRahul- IIT Roorkee
```
7 years ago
Kushagra Mishra
35 Points
```										how is ac=121?I dont get it xD :/
```
2 years ago
Premanshu Rao
25 Points
```										Why did we reject -22?
```
2 years ago
Akshay
185 Points
```										you will not reject -22, a=-11,b=-99,c=-11,d=-99 is also a possible solution. Just substitute and check
```
2 years ago
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