MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
Rohit Singh Grade: 12
        

4.     if sin θ and cos θ are the roots of the equations ax2-bx2+c = 0, then a, b and c satisfy the relation.


(a)    a2+b2+2ac=0


(b)    a2-b2+2ac=0


(c)    a2+c2+2ac=0


(d)    a2-b2-2ac=0

6 years ago

Answers : (1)

Chetan Mandayam Nayakar
312 Points
										

sin2(theta) + cos2(theta) = (sinθ +cosθ)2 -2sin(theta)cos(theta) =1


sin(theta) +cos(theta) = -b/a, sin(theta)cos(theta) =c/a


therefore b2/a2 -2c/a =1, a2-b2 +2ac=0 


'Win exciting gifts by answering the questions on Discussion Forum.'

6 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: R 15,000
  • View Details
Get extra R 3,000 off
USE CODE: CART20
Get extra R 440 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details