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4.     if sin θ and cos θ are the roots of the equations ax2-bx2+c = 0, then a, b and c satisfy the relation.

(a)    a2+b2+2ac=0

(b)    a2-b2+2ac=0

(c)    a2+c2+2ac=0

(d)    a2-b2-2ac=0

6 years ago


Answers : (1)


sin2(theta) + cos2(theta) = (sinθ +cosθ)2 -2sin(theta)cos(theta) =1

sin(theta) +cos(theta) = -b/a, sin(theta)cos(theta) =c/a

therefore b2/a2 -2c/a =1, a2-b2 +2ac=0 

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6 years ago

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